四时宝库

题目如下

解决思路如下：

找一个本子，把算法思路画下来。可以写的杂乱，后续把思路和流程图画清楚即可。

具体代码实现：

import random

def get_input(): #获取密钥串的长度，获取密钥串中特殊字符的个数，获取密钥串中数字的个数，并返回
    pswdlength=input("What's the minimum length")
    speclength=input("How many special characters?")
    numblength=input("How many numbers?")

    return pswdlength,speclength,numblength

def randomspecial():#返回随机特殊字符
    lista=('~',"!","@","#","#34;,"%","&","*","(",")","_","+","-","=")
    i=random.randint(0,len(lista)-1)
    return lista[i]

def randomcharacter():#返回随机字母
    listb=("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z")
    j=random.randint(0,len(listb)-1)
    return listb[j]

def producelist(pswdlength,speclength,numblength): #产生一个列表
    list = {}
    pswdlength = int(pswdlength)
    speclength = int(speclength)
    numblength = int(numblength)
    leftlength = pswdlength - speclength- numblength
    for i in range(0,pswdlength):
        if speclength>0:
            list[i]=randomspecial()
            speclength = speclength - 1
        elif numblength>0:
            list[i]=random.randint(0,9)
            numblength = numblength - 1
        elif leftlength>0:
            list[i]=randomcharacter()
            leftlength = leftlength - 1
    #print("字符串长度是{0}".format(len(list))) #debug 用
    return list

def randomlizelist(list): #交换算法，遍历key,随机和字典里面其它的key下的value进行交换。
    listlength = len(list)
    for i in range(0,listlength-1):
        j = random.randint(0,listlength-1)
        temp = list[i]
        list[i] = list[j]
        list[j] = temp
    return list


if __name__ == '__main__':
      pswdlength,speclength,numblength = get_input()
      list=producelist(pswdlength,speclength,numblength)
      list=randomlizelist(list)
      print("Your password is ",end="")
      for i in range(0,len(list)):
          print(list[i],end="")
      #debug 用 print("")#debug 用
      #debug 用 print(list)#debug 用

效果图：